Two square metal plates with sides 6.24 mm that are 5.97 mm apart have 2.17 nC...
Two square metal plates with sides 6.24 mm that are 5.97 mm apart have 2.17 nC of charge placed on them. What is the potential difference between the plates?
Homework Answers
It is a parallel plate capacitor
A = side*side
= (6.25*10^-3)*(6.25*10^-3)
= 3.91*10^-5 m^2
d = 5.97*10^-3 m
C = ebsolene0*A/d
= (8.854*10^-12)*(3.91*10^-5)/ (5.97*10^-3)
=5.79*10^-14 F
use:
V = Q/C
= (2.17*10^-9)/(5.79*10^-14)
= 37456 V
Answer: 37456 V
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