Apply node equation at point C.
Current through resistor R2 will be (I1+I2).
Apply loop equation to the left loop -
125 - E = R2(I1+I2) + I1*R1 = 3(2.5+9.0) + 2.5*7.0 = 52
=> E = 125-52 = 73 V
Now, apply loop equation in the right loop -
125 = R2(I1+I2) - I2*R = 3(2.5+9) + 9*R
=> 9R = 125 - 34.5 = 90.5
=> R = 10.05 Ohm
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