A point charge of 1.26x10^-10 C is mobed by an external agent through an electric field...
A point charge of 1.26x10^-10 C is mobed by an external agent through an electric field from point A at an electric potential of 6.32Volts to 12.4Volts. This particle begins and ends at rest. How much work was done by the agent?
Homework Answers
Using work energy theorem ,
work done by agent + work done by Electric Field = Change in K.E.
W + qV = 0
W = -qV = - 1.26 x 10^-10 x (6.32 - 12.4) = 7.66 x 10^-10 J
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