An alpha particle, which has charge 3.20 ✕ 10−19 C, is moved from point A, where the electric potential is 3.40 ✕ 103 J/C, to point B, where the electric potential is 5.10 ✕ 103 J/C. Calculate the work in electron volts done by the electric field on the alpha particle.
An alpha particle, which has charge 3.20 ✕ 10−19 C, is moved from point A, where...
A particle of net charge, +Q, is moved from point (A) to point (B) along the path shown in the figure below. We want to calculate the voltage difference between the end point, (B), and the start point, (A), for the particle. 3 5 m 寸 3 m Assume the electric field has a magnitude of E 55.8 , and the particle has a net positive charge of Q5.40 C. Calculate the magnitude of the electric potential difference, Enter answer...
1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗ directed to the negative x direction. It is released from rest, and after it has moved 6.00 cm , its kinetic energy is found to be 1.50×10−6 J . a. What work was done by the electric force? b. What was the change in electric potential over the distance that the charge moved? c. What is the magnitude of E? d. What was the change...
When an alpha particle, which has charge +2e, moves from a point with an electric potential equal to 250 V to a point with an electric potential of 1,250 V, what is the change in the electric potential energy?
Problem 2 A particle with charge +7.60 nC is inside a uniform electric field directed to the left. Another force, in addition to the electric force, acts on the particle so that when it is released from rest, it moves to the right. After it has moved 8.00 cm, the additional force has done 6.50-10-4 J of work and the particle has 4.35-10-5 J of kinetic energy. (a) What work was done by the electric force? (b) What is the...
A small particle has charge -4.50 μC and mass 3.00×10−4 kg . It moves from point A, where the electric potential is VA = 200 V , to point B, where the electric potential VB = 530 V is greater than the potential at point A. The electric force is the only force acting on the particle. The particle has a speed of 5.10 m/s at point A.
A charge is moved from position A where the electric potential is 30 v to position B with electric potential 400 v. As the particle moves, its electric potential energy increases by APE=4.1x10-5 J. What is the electric charge of the particle? 9.0 MC 400 C O 110 nC 370 C 15 mc What is the electric potential energy of the electron in the figure? Both particles are fixed and can't move. Electron 3.0 nm Proton 1.2 nm O 22x10-11)
A particle has a charge of +2.6 ?C and moves from point A to point B, a distance of 0.23 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.1 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the...
A particle with a mass of 6.4 × 10–27 kg and a charge of +3.20 × 10–19 C is accelerated from rest through a potential difference of 9.0 × 106 V. The particle then enters a uniform 0.82-T magnetic field. If the particle’s velocity is perpendicular to the magnetic field at all times, what is the magnitude of the magnetic force exerted on the particle?
A small particle has charge q and mass 2.00×10-4 kg. It moves from point A, where the electric potential is VA = +400 V, to point B, where the electric potential is VB = +800 V. The electric force is the only force acting on the particle. The particle has speed 5.00 m/s at point A, and a speed of 4.25 m/s at point B. What is the charge of the particle q?
A particle with a charge of +4.20 nC is in a uniform electric field È directed in the negative x direction. It is released from rest, and after it has moved 6.00 cm, its kinetic energy is found to be + 1.50 × 10-6 J. (a) what work was done by the electric force? (b) What was the change in electric potential over the distance that the charge moved? (c) What is the magnitude of E? (d) What was the...