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A 20cm x20cm square loop has a resistance of 0.10 ohms. A magnetic field perpendicular to...

A 20cm x20cm square loop has a resistance of 0.10 ohms. A magnetic field perpendicular to the loop is B= 4t -2t^2, where B is in tesla and t is in seconds. What is the current in the loop at t =0.0s , t=1.0s and t=2.0s?

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Answer #1

a) Since the field is perpendicular to the plane of the loop A is parallel to B , so φ-AB and ε=le1Φ / dt-AdB/ d. Since B= 41

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