Answer
Molarity of Mg(OH)2 = 0.8367M
Percent mass of Mg(OH)2 = 4.875M%
pOH = 0.22
pH = 3.78
Explanation
Mass of evoparating dish = 40.380g
Mass of evoparating dish + Dried mass of Mg(OH)2 = 40.868g
Difference in mass = 40.868g + 40.380g = 0.488g
mass of Mg(OH)2 = 0.488g
molar mass of Mg(OH)2 = 58.320g/mol
No of mole of Mg(OH)2= 0.488g/58.320g/mol= 0.008367mol
Volume of solution = 10ml
Molarity of Mg(OH)2 = (0.008367mol/10ml)× 1000ml = 0.8367M
[OH-] = 2×0.8367M = 1.6734M
pOH = 0.22
pH = 14 - pOH
pH = 14 - 0.22 = 13.78
Mass of evoparating dish + Mg(OH)2 solution = 50.391g
Mass of evoparating dish = 40.380g
Mass of Mg(OH)2 solution = 10 011
Mass of Mg(OH)2 = 0.488g
Percent mass of Mg(OH)2 = (0.488g/10.011g)×100 = 4.875%
23. Find the molarity and percent mass of the Mg(OH)2 solution using the information below. (12...
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