Question

1. You’re driving down the highway late one night at 20 m/s when a deer steps out onto the road 35 m in front on you. Your reaction time before stepping on the brakes is 0.50 seconds and the maximum deceleration of your car is 10 m/s2.

a) How much distance is between you and the deer when you come to a stop?

b) What is the maximum speed you could have and still not hit the deer?

2. Consider the two vectors A = 3 i – 2 j and B = - i -4 j.

Calculate the following: A + B, A – B, |A + B|, |A – B| and the directions (conventional angles) of A and B.

Answer 1

0 u= BOMIS 35 m t= 0.55 Let, so=distance covered = 2 deer t=0s speed = constant = 35 m/s Si=distance travelled = ut = 20x0.5= maam (lom After 0.55 I Break is applied Then it's stopped (V=O) 20 = 20m 2C-10) ai – 10m/s2 o 2. ہر 2 - 2a

2. Here ☆ - 3ê -2 B²=-2 - 4 Atb A-B B | ATBL IA-BI between ASB o= angle ① Ā + B = 3ê ê -27_u - i - 6 ② Ā B = 3? - 2} + 2 + y} ५२+2 (3) / A+B) = √2² + (-62 = 54 +36 = V Juo=2VTO W|A-Bl=542+ z² = √16+4 = 20 = (6) To calculate angle 'o' AB IĀ 15/1999 y coso=Ā . AlfB1 / 32422 / 12 +42 V13 17 - 3+ 8 5 -) Q 14.86 cos-l Acos 70.33 3) 14.86) Please rate it. Thank u!!!