Question

opnicate Choice of will learn to the electiokyticsolution. PRE-LAB 1. Calculate the "theoretical yield" of copper that could be plated after running an electro-remediation cell for 0.50 amps at 2.00 volts for 10 minutes. 2. What leads on the power source should be connected to the anode and cathode to run an electro-remediation cell to remove Cu²+ from solution? 3. Consider the half-reaction shown in Scheme 1: how will the pH, the conductivity, and required voltage change if an electrolytic cell, used to reduce copper, is run at an over-potential that allows water to be oxidized?! PROCEDURES 1. Record the mass of the clean dry stainless steel cathode. 11 wn in Figure 11-3. Use a continuous po

Answer 1

souhon Given that I cu 2+ + 2 ē - cu Current C) = 0.50 A = 0.56c/s = 600 sec Hime (t) = 100 min x 60s mio charge (a) = current & time = 0.50 cls x 600 s I charge a = 300c charge carried by one mole elechons = 96500 c. charge carried 2 mole elechons =2x 96500 Automic mals cu z 63:5g. 2 mole electrons deposit 63.5 g cu charge required to depourt 63.59 cu ü 2965000 a calculate the mass of lu to deposit for 300c by using the following conversion: mass or cu ho deposit = 300 x 63.5g cu - 2x 9650oC Hence o.oqaga is plated 0.099gcu out of the solution

consider the half reachion. 1. The half reach on of an electrolytic cell is - 02+uh tué - 2H₂O e = 1.23 The given elecholytic cell is used to reduce coprą Reaction : catha) + zł - cucs) t = 0.34 The elecholy hic cell is van at an over potential allowing water to be oxidize de ther. Reachon :- 2H2011) 02(g) tuttaa) tue --1.231 reaction as follows © & reach on by the combing the rea Reachoon 0x2 + peachon ® Cuct 02 (9) + 41, cu+200) + 2H; Oce) - É cell = 28 treactint EⓇreacheon fecell = 24 0:34+ 61.23) =-0.55V nernest canation, t cell = tcell - 003 wsing u xin [at] {cu tz]

teen - Eren - o: osaa log CF 14 - cut2]. Ecen = -0.55- 0.0592 - log [ft] [cuta). fcell to.55 -Eclogs H+7 + Ve log[cutz) o-osar pH fcell to'SS - log [ cute 0.0592 from the above cauation it is clear that it the cell is ran after over potenhal the pH of the cell is increased. • Conduchiety aut "(the higher the pH , the lower the pH concentral the lower the conduchivity] thus, conductivity of the solution is de reased Also the required voltage is also increased.