Question

Consider the following segment table: Segm 0 1 Base Length 400 500 1000 500 2000 200 ent Whai are thee physsicall addresses for tthe loggicall addresst a. 0,431 b. 0,900 C. 2,240

Answer 1

a.

Physical address is 400 + 431 = 800

b.

Physical address is 400 + 900 = 1300

But segment 1 is of length 500.

logical address > segmentation length

i.e 500 > 431

So, segnemtaton fault

c.

Physical address is 2000 + 240 = 2240

logical address > segmentation length

i.e 240 > 200

So, segnemtaton fault

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