What is the pKa of an acid that has a Ka of 2.72*10^-4? please show all work :)
given, Ka = 2.7210-4
as pKa = -log10[Ka]
pKa =
-log10(2.7210-4)
pKa= -log10(-4) - log10(2.72)
pKa = 4 - 0.4345
pKa = 3.56
What is the pKa of an acid that has a Ka of 2.72*10^-4? please show all...
A certain organic acid has a Ka of 5.01 × 10−4. What is its pKa?
The acid dissociation constant ka for an acid is 1x10-6 what is the pka? show the work
Boric acid has a Ka of 5.8 × 10-10. What is the pKa? Assume boric acid is H3BO3 and is monoprotic.
A certain acid has pKa = (7.997x10^0). What is the acid's Ka? (Ka, Kb, pKa, and pKb are unitless quantities.)
If the equilibrium constant for the acid dissociation is KA and pKA (-log Ka) =7.0, what is the ratio of [HPO42-] to [H2PO4−] in this buffer system? Please show your calculation.
Ka = 10^(-pka) if ka is 1.8E-5 then, solve for Pka for acetic acid.
Question 2 Boric acid has a Ka of 5.8 × 10-10. What is the pKa? Assume boric acid is H3BO3 and is monoprotic. Question 3 A 0.25 M solution of boric acid is mixed with a 0.75 M solution of NaOH. What is the pH of the solution if 7.5 mL of boric acid is mixed with 5 mL of NaOH? Question 4 What volume of boric acid solution (in mL) is required to fully neutralize the sodium hydroxide solution?
Calculate the pka and ka given the pH.
Please show ALL steps
measured pH = cal, pKa = q. I 0 pH1 after 5 drops of NaOH-14- pH after 5 drops of HCl = gng BE SURE TO GET T 3) Buffer System with 2 ml acid + 20 ml conjugate base [B]/ [HB] = 10 BE SURE TO GET THIS CORRECT!! (use "H+H" Eq. above to calculate pKa) measured pH- 450 pH after addition of XS NaOH-10.00 dition of...
a) The Ka for acetic acid (H3CCO2H) is 1.737 × 10–5. What is the pKa for this acid? b) Use the pKa calculated above to determine the pH at which [H3CCO2H]=[H3CCO2-].
Ka=10^-pKa
Phosphoric acid, H_3PO_4(ag), is a triprotic acid, meaning that one molecule of the acid has three acidic protons. Estimate the pH, and the concentrations of all species in a 0.400 M phosphoric acid solution.