A certain organic acid has a Ka of 5.01 × 10−4. What is its pKa?

Question

Question

Answer 1

Answer #1

Given ka = 5.01 x 10^-4

pKa of an acid = - log Ka

= -log (5.01x10^-4))

= -log 10^-4 - log 5.01

= 4 -log 5.01

=3.30

Answer 2

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