7. Using resonance structures show how the amino group would effect the electron density on the ring carbons of the following compound. Would you expect an electrophile to attack this molecule at the ortho, meta or para position(s)?
8. Draw the structure of (3R,
4R)-3-(3-fluorophenyl)-4-formylhexan-2-one
Homework Answers
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7. Using resonance structures show how the amino group would
effect the electron density on the...
1. Using resonance structures, show why the amino group is activating. Consider an attack by the...
1. Using resonance structures, show why the amino group is activating. Consider an attack by the electrophile E+ at the para position.
When there is an electron-withdrawing group on a benzene ring (eg. compounds such as nitrobenzenebenzoic acid,...
When there is an electron-withdrawing group on a benzene ring (eg. compounds such as nitrobenzenebenzoic acid, acetophenone, etc, resonance structures can be drawn that indicate the positions on the benzene ring that are least nucleophilic (because they have a positive charge on the carbon at that position). Because these positions are much less nucleophilic, the substitution reaction will not occur here; instead, substitution will occur at the other position(s) on the ring. As a result, which position(s) are most nucleophilic...
Question 3 1s 3 ORTHO Today we learned about adding a second group to a mono-substituted...
Question 3
1s 3 ORTHO Today we learned about adding a second group to a mono-substituted benzene ring. Any group on a benzene will affect the rate of the reaction (activated or deactivated relative to benzene) and the regioselectivity Where does the electrophile add? Ortho? Meta? Para? Some combination thereof? We found that EDGs (electron-donating groups) direct the electrophile to the ortho and para positions while EWGs (electron-withdrawing groups) direct the electrophile to the meta position. Now, it is time...
Using resonance structures as part of your answer, explain why Br in bromobenzene is: a. A...
Using resonance structures as part of your answer, explain why Br in bromobenzene is: a. A mild ring deactivator b. An o-, p-director. [Note: It is not enough to use resonance structures from part "a" to "prove" part "b". One must show that o-, p-attack is faster, i.e. has lower Ea (AGa) by actually showing an electrophile, e.g. the generalized E+, attacking at the o-, m-& p-positions and, using Hammond's Principle, explain why the o-, p-attacks are favored.] Explain what...
given Which is more stable? Position A/ Position B (circle one) COOH COOH Which is more...
given
Which is more stable? Position A/ Position B (circle one) COOH COOH Which is more stable? Position A/ Position B (circle one) 9. Given the results of the previous problems, if an ELECTRON DONATING group is already attached to benzene, it is more stable to add the electrophile to the _position(s). Look at positions A and B in the previous problems. a. Ortho b. Meta C. Para d. Two of the above e. None of the above 10. If...
2. Not only does an aromatic ring itself affect the reactivity of an acid derivative (an ester, o...
2. Not only does an aromatic ring itself affect the reactivity of an acid derivative (an ester, on last year's quiz), substituents on the aromatic ring can further modify the reactivity. First, we will consider a phenyl amide with a para-acetyl substituent: CH, (a) What is the n-effect (resonance) of the para-acetyl substituent? How will that affect the reactivity of the other (amide) carbonyl in the molecule below (increase or decrease, compared to the same amide but with no p-...
1. please check what is wrong. Thank you! Determine the product formed when each compound is treated with...
1. please check what is wrong. Thank you!
Determine the product formed when each compound is treated with Br2 and FeBr3. Drag the atom labels to their appropriate positions. CN Atom labels H H Br Br2 A. FeBr Br H OH OH Br Br. Br2 FeBr3 H H Br Br H Br2 FeBr H1 H Reset T Rank the compounds in each group in order of decreasing reactivity in electrophilic aromatic substitution. CI Decreasing reactivity Rank the compounds in each...
1.The best way to describe the "arrow" showing the mechanism of EAS is: A.it goes from...
1.The best way to describe the "arrow" showing the mechanism of EAS is: A.it goes from the attacking atom (electrophile) to the carbon being attacked. B.it goes from the attacking atom to the new bond being formed. C.it goes from the electron pair in the pi-bond on the ring to the new sigma bond being formed. D.it involves a half-head arrow from the attacking species and a half-head arrow from the pibond to the new sigma bond to be formed....
please help in all sections asap! The following two drawings are resonance structures of one compound....
please help in all sections asap!
The following two drawings are resonance structures of one compound. a-o But the following two drawings are not resonance structures Not resonance structures They are, in fact, two different compounds. Choose the correct explanation(s). Select all that apply. Benzene does not have three C-C single bond and three C-C double bonds. In fact, all six C-C bonds of the ring have the same bond order and same length. Benzene have three C- single bond...
use the notes provided to help answer the question above. will rate well The second step...
use the notes provided to help answer the question
above. will rate well
The second step of the synthesis transformation of the chlorosulfonyl functional group into a sulfonamide) is an example of a a. Nucleophilic displacement (substitution) b Elimination C. Electrophilic aromatic substitution d. Acid hydrolysis Esterification e. THE SULFONIC ACID GROUP AND ITS DERIVATIVES Sulfonic acids are organic analogs of sulfuric acid, a very strong acid. They are highly corrosive, react vigorously with water, and can cause skin bums....
1. Using resonance structures, show why the amino group is activating. Consider an attack by the electrophile E+ at the para position.
When there is an electron-withdrawing group on a benzene ring (eg. compounds such as nitrobenzenebenzoic acid, acetophenone, etc, resonance structures can be drawn that indicate the positions on the benzene ring that are least nucleophilic (because they have a positive charge on the carbon at that position). Because these positions are much less nucleophilic, the substitution reaction will not occur here; instead, substitution will occur at the other position(s) on the ring. As a result, which position(s) are most nucleophilic...
Question 3
1s 3 ORTHO Today we learned about adding a second group to a mono-substituted benzene ring. Any group on a benzene will affect the rate of the reaction (activated or deactivated relative to benzene) and the regioselectivity Where does the electrophile add? Ortho? Meta? Para? Some combination thereof? We found that EDGs (electron-donating groups) direct the electrophile to the ortho and para positions while EWGs (electron-withdrawing groups) direct the electrophile to the meta position. Now, it is time...
Using resonance structures as part of your answer, explain why Br in bromobenzene is: a. A mild ring deactivator b. An o-, p-director. [Note: It is not enough to use resonance structures from part "a" to "prove" part "b". One must show that o-, p-attack is faster, i.e. has lower Ea (AGa) by actually showing an electrophile, e.g. the generalized E+, attacking at the o-, m-& p-positions and, using Hammond's Principle, explain why the o-, p-attacks are favored.] Explain what...
given
Which is more stable? Position A/ Position B (circle one) COOH COOH Which is more stable? Position A/ Position B (circle one) 9. Given the results of the previous problems, if an ELECTRON DONATING group is already attached to benzene, it is more stable to add the electrophile to the _position(s). Look at positions A and B in the previous problems. a. Ortho b. Meta C. Para d. Two of the above e. None of the above 10. If...
2. Not only does an aromatic ring itself affect the reactivity of an acid derivative (an ester, on last year's quiz), substituents on the aromatic ring can further modify the reactivity. First, we will consider a phenyl amide with a para-acetyl substituent: CH, (a) What is the n-effect (resonance) of the para-acetyl substituent? How will that affect the reactivity of the other (amide) carbonyl in the molecule below (increase or decrease, compared to the same amide but with no p-...
1. please check what is wrong. Thank you!
Determine the product formed when each compound is treated with Br2 and FeBr3. Drag the atom labels to their appropriate positions. CN Atom labels H H Br Br2 A. FeBr Br H OH OH Br Br. Br2 FeBr3 H H Br Br H Br2 FeBr H1 H Reset T Rank the compounds in each group in order of decreasing reactivity in electrophilic aromatic substitution. CI Decreasing reactivity Rank the compounds in each...
please help in all sections asap!
The following two drawings are resonance structures of one compound. a-o But the following two drawings are not resonance structures Not resonance structures They are, in fact, two different compounds. Choose the correct explanation(s). Select all that apply. Benzene does not have three C-C single bond and three C-C double bonds. In fact, all six C-C bonds of the ring have the same bond order and same length. Benzene have three C- single bond...
use the notes provided to help answer the question
above. will rate well
The second step of the synthesis transformation of the chlorosulfonyl functional group into a sulfonamide) is an example of a a. Nucleophilic displacement (substitution) b Elimination C. Electrophilic aromatic substitution d. Acid hydrolysis Esterification e. THE SULFONIC ACID GROUP AND ITS DERIVATIVES Sulfonic acids are organic analogs of sulfuric acid, a very strong acid. They are highly corrosive, react vigorously with water, and can cause skin bums....
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