Question

Suppose we had a bulk liquid (marked with a red tr

A) if the liquid was cooled to temperature T4, what phases would be present? what would be the weight % B in each phase?

B) What would the relative proportions of solid and liquid be at that T4? please show your work

C) What woud the total weight % of A and of B be in the system at temperature T2?

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Answer #1

A) If initial composition of B = 75%... It start in liquid phase! Then lower temperature until you achieve the equilibrium line! Afterwards, follow that equilibrium line until you achieve "g" point". You will have phases Liquid Melt and the solid crystal "beta" in equilibrium. The melt composition is about 68% (that composition of "g" point) The composition of the solid crystal is of course 100%.

B) If you wanted to calculate the portions of Liquid mixture and Solid Crystal... Do a mass balance

Basis = 100 grams of feed (25 grams of A and 75 grams of B)

Product when cooled => two phases, liquid (A+B) and solid (B)

Lets calculate how much of B is left in the liquid phase:

(B left in solution) / (A left in solution + B left in solution) = %Mass Weight of B

(B left in solution) / (25g + B left in solution) = 0.68

B = (25+B)

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