2. Solve the following systems using elimination: -2x + y = 1 (a) , 4x -...
Solve the systems of equations by substitution #11 2x-y-2 3x+4y-6 Solve each system by elimination or by any convenient method #13 a) 3x+4y-1 2x-3y-12 b) -4x+3y--!5 3x-2y-4
solving using Gaussian elimination method to solve the questions above 1. Solve the following systems of linear equations using Gaussian elimination method. a) 3z 9 x 5y 2z 2 1 3 *+2y = 3 b) x+y 0 2x y+3z3 x-2y -z 3 c) xy+z 9 2x +4y-3z= 1 3x+6y 5z= 0 e) 2xz w 5 y-w-1 3x z-w 0 4x +y+ 2z +w 9 2. How many gallons of each of a 60 % acid solution and an 80 %...
Systems of equations: solve using elimination method X+2y-z = -6 3x-y+z = 8 4x-y-2z = 0
The Golus Elimination method: Example: Solve the system: 2x +y +2 = 5 4x-by = -2 -2x + 7y +22=9
Systems of Equations: 3x + y = 6 2x-2y=4 Substitution: Elimination: Solve 1 equation for 1 variable. Find opposite coefficients for 1 variable. Rearrange. Multiply equation(s) by constant(s). Plug into 2nd equation Add equations together (lose 1 variable). Solve for the other variable. Solve for variable. Then plug answer back into an original equation to solve for the 2nd variable. y = 6 -- 3x solve 1" equation for y 6x +2y = 12 multiply 1" equation by 2 2x...
Solve the system of equations using matrices. Use Gauss-Jordan elimination. 5) 5) -2x-y-5z =-38 4x + 2y-2z= 28 4x-5y + z=-16 A) ((-5, 8, 10) D) ((10, 8,-5) B) (5, 8,4)) C) (5, 4,8) Solve the system of equations using matrices. Use Gauss-Jordan elimination. 5) 5) -2x-y-5z =-38 4x + 2y-2z= 28 4x-5y + z=-16 A) ((-5, 8, 10) D) ((10, 8,-5) B) (5, 8,4)) C) (5, 4,8)
Using matrices to solve systems of equations 1. 2x- 3/2y=-9 2x+y=-4
Solve the following linear systems of equations by Gaussian elimination. 3x+3z=0 2x+2y=2 3y+3z=3
Ð. Solve the following system of linear equations by Gaussian elimination: 4x + 4y + 4z = 8 2x + y + z = 3 2x - 2y + 6z = 16 Show all your work and explain every step of the process.
3. Solve the following systems of equations using Gaussian elimination. (a) 2x 3x2 + 2x3 = 0 (d) 2x + 4x2 2.xz 4 *- x2 + x3 = 7 X; - 2x2 · 4x3 = -1 -X, + 5x2 + 4x3 = 4 - 2x - X2 3x3 = -4