Estimate the average force exerted by a shot-putter on a 7kg shot if the shot is moved through a distance of 2.6m and is released with a speed of 10m/s
initial velocity vi=10m/sec
final velocity vf=0m/sec
s=2.6m
thus by equation of motion
vf2-vi2=2as
|a|=vi2/2s= 19.23m/sec2
now by newton's second law
F=ma= 7kgx19.23m/sec2=134.61N
w = change in K.E ...
F*s = (1/2)*m*(v^2)...
F = (1/2)*m*u^2/s....
F = 134.6 N
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