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Example # 4: Some people love roller coasters. Prof. Bodrero found a site with info on hundreds of coasters in the US. He won

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Answer #1

a)

1586832925425_image.png

where x= height of roller coaster

y = speed of roller coaster

b) The correlation coefficient is given by

r=\frac{n\sum xy-\sum x\sum y}{\sqrt{n\sum x^{2}-(\sum x)^{2}}\sqrt{n\sum y^{2}-(\sum y)^{2}}}

Calculation

x y x^2 y^2 xy
58 105 3364 11025 6090
13 62 169 3844 806
27 81 729 6561 2187
57 113 3249 12769 6441
30 96 900 9216 2880
44 100 1936 10000 4400
30 81 900 6561 2430
26 78 676 6084 2028
24 83 576 6889 1992
49 105 2401 11025 5145
sum 358 904 14900 83974 34399

Thus

r=\frac{10*34399-358*904}{\sqrt{10*14900-(358)^{2}}\sqrt{10*83974-(904)^{2}}}

= 0.9397

r^2=0.8831

Interpretation : r^2 is called coefficient of determination which is interpreted as , 88.31% change in y variable (dependent variable) can be explained by x variable(independent variable) .

c) The null and alternative hypothesis

H0:\rho =0

Ha:\rho \neq 0

Test statistic

? = لا 2 - rvnے

= 7.77

degrees of freedom = n-2 = 8

For 9= 0,05 , with df = 8 , critical value of t is

tc = 2.31 ( from ta table )

Since t > 2.31

Reject H0

there is sufficient evidence to conclude that linear correlation exists between height and speed of roller coaster .

d) The equation of line of regression is

y=\alpha +\beta x

where estimates of \alpha ,\beta are

a= \frac{\sum y\sum x^{2}-\sum x\sum xy}{n\sum x^{2}-(\sum x)^{2}}=55.42

b= \frac{n\sum xy -\sum x\sum y}{n\sum x^{2}-(\sum x)^{2}}=0.98

Thus ,estimated line of regression is given by

\hat{y}=55.42+0.98x

e) x=40 meter

predicted maximum speed is

\hat{y}=55.42+0.98*40= 94.62 km /hr

f) Slope is =0.98

Thus for each meter increase in x , y is expected to increase by 0.98 km/hr

d) The graph of regression equation in scatter plot

1 10 20 30 40 50 60 70

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