SOL:
double(x) is the correct answer
so First option is correct answer
Explanation:
Typecasting means we are converting one datatype to another datatype
we want to convert a integer to double so we keep integer variable in braces and before that double datatype is placed
so double(x) is the correct answer
Which of the following is a correct way to typecast an integer to a double? double(x)...
a) Make a function which returns x/3 with a given integer x. double third(int x) { //Complete your code below. ______________________________________ return y; } b) Make a program which shows 2 ∗ n with a given user input n. #include<iostream> using namespace std; // Complete the blank. _______________________ int main(){ int n; cout<<"Enter:"; cin>>n; cout<<twice(n); return 0; } int twice(int x){ return 2*x; } c) Make a function which returns true if n is positive, otherwise returns false. ________ positive(int...
C programming Given an integer variable declared as int result, which of the following choices set result = 2? Each choice may contain a single statement or a group of statements. Select all choices you believe are correct--this question may have more than one correct answer! A. double temp = 19.0; int div = 10; result = 1 + temp / div; B. double val1 = 3; double val2 = 0.75; result = val1 / 2 + val2 * 2; C....
Which one is correct? Thanks. Please give a simple
explanation.
Assuming that class X has a function: void func (int x) Which of the following functions could not be added to class x: Select one: a. int func (double x) b. void func() c. int func (int x) o d. void func(double
(5.00 Points) 11 - The function prototype double mySqrt(int x); defines a function called a) double which calculates square roots b) mySqrt which takes an integer as an argument and returns a double c) mysqrt which takes an argument of type x and returns a double d) mysqrt which takes a double as an argument and returns an integer
Given the function definition, which of the following are correct? int func(int n, double d) { int j = n; double sum = 0; while( j >= 0) { sum += d; -j; } return sum; } It compiles but computes none of these returns 7+2 returns 7! returns 7*2
what are the answes
Which yields 2.5? (double)(10/4) (int)(10) / (int)(4) 10/4 (double)(10) / (double)(4) Considering integer division, determine the result of 13 / 3 4.3 05 4.0 4 Which of the following statements is a valid declaration of a constant integer variable named STEP_SIZE? int STEP_SIZE = 5; O final int STEP_SIZE = 14; double STEP_SIZE = 5; final STEP_SIZE = 10; Which is an invalid identifier? num_Cars1 3numCars O_numCars numCars Which one is not a programming language. Java...
For two given array declarations: int x[3] and double y[3], which of the following is FALSE? o the memory size of x and y is same. O the last element of y is at subscript 2 O x and y are located at different memory locations o y can store the value 3.14 at any of its valid index
Given an integer x which is assumed to be in the list
a, write a method that returns the position of the first occurrence
of x in a. Positions are counted as 0,1,2,.... If x does not appear
in the list, you should throw an IllegalArgumentException.
static int find(int x, List<Integer> a) Given an integer x which is assumed to be in the list a, write a method that returns the position of the first occurrence of u in a....
Which of the following is the correct way to code a try statement that displays the type and message of the exception that’s caught? try: number = int(input("Enter a number: ")) print("Your number is: ", number) except Exception as e: print(e(type), e(message)) try: number = int(input("Enter a number: ")) print("Your number is: ", number) except Exception as e: print(type(e), e) try: number = int(input("Enter a number: ")) print("Your number is: ", number) except Exception: print(Exception(type), Exception(message)) try: number = int(input("Enter...
Show the symbol table and activation record for the following function. double cubic(double x, int a, int b, int c, int d) { double y = 0.0; y = a*x*x*x + b*x*x + c*x + d; return y; }