Question

Calculate the quantity of potassium sulfate formed if 100.0 grams of each of the following react: vanadium, sulfuric acid and potassium dichromate. The main product from the vanadium is vanadium (V) sulfate

Answer 1

Balanced chemical equation 6V + 35 H_2 SO_4 + 5 K_2 Cr_2 O_7 rightarrow 5 Cr_2 (SO_4)_3 + 3 V_2 (SO_4)_5 + 35 H_2 O + 5 K_2 SO_4 grams of V = 100.0 g grams of H_2 SO_4 = 100.0 g gram of K_2 Cr_2 O_7 = 100.0 g molar mass of V = 59.94 g/mol molar mass of H_2 SO_4 = 98.079 g/mol molar mass of K_2 Cr_2 O_7 = 294.185 g/mol number of moles = grams (g)/molar mass (g/mol) \r\n moles of V = 100.0 g/59.94 g/mol = 1.67 mol moles of H_2SO_4 = 100.0 g = 1.02 mol moles of K_2 Cr_2 O_7 = 100.0 g/294.185 g/mol = 0.34 mol How to find limiting reagent? substance which has the beast value of ratio of number of moles/stoichiometric coefficient will be limiting reagent 6V + 35 H_2Cr_2 O_7 rightarrow 5 Cr_2 (SO_4)_3 + 3 V_2 (SO_4)_5 + 35 H_2O