Question

8.2.10-T 5 of 52com Considera drug that is them that of the preve d e in a Doc HW Score: 20%, 105 Gestione Use a 0.05 significance level tobe mong 60 r chon? tried with this drug 148 developed the adverse reaction of dertly the null and alternative hypothes for th e con AH D03 H: 003 PI p>003 Hp.03 H0.03 DH03 HOOD by the Theory (Round tower More 3

Answer 1

Solution :

This is the two tailed test .

The null and alternative hypothesis is

H₀ : p = 0.03

H_a : p $\neq$ 0.03

$\hat p$ = x / n = 148/6083 = 0.0243

P₀ = 0.03

1 - P₀ = 1-0.03 = 0.97

Test statistic = z

= $\hat p$ - P₀ / [$\sqrt$P_{0 *} (1 - P₀ ) / n]

=0.0243 - 0.03 / [$\sqrt$003*(0.97) /6083 ]

= -2.59

P(z < -2.59) = 0.0096

P-value = 0.0096

The hypothesis test is = -2.59