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Chapter 11, Section 11.3, Question 047 Suppose f (x) has zeros at x = -1, x = 5, x = 7 and a y-intercept of 17. In addition,Give a possible formula of minimum degree for the polynomial h (x) in the graph below. 1 2 3 4

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minimal possible degree = 2. fo = c(x+1) (x-5) (1-7) when x=0, f(u) = 17. 17- ((1) (-5)(-7) CO f(u) = (x+1)(x-3)(x-7)flul 17 (+1) (R-5) (x-7) 35 Post 2 - since it has 4 roots. minimal polynomial degree=4

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