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Given the Host IP address 14.82.19.54 A. Express the address in binary. B. What is the...

Given the Host IP address 14.82.19.54

A. Express the address in binary.

B. What is the class?

C. What is the Host ID?

D. What is the Network ID?

E. What is the directed broadcast address?

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Answer #1

Given the Host IP address 14.82.19.54

A. Express the address in binary.

Answer:

00001110.01010010.00010011.00110110

[Just convert all the decimal number in 8-bits binary system and represent in the dotted delimiter]

B. What is the class?

Answer:

class A, since first octet (byte) started with 0.

C. What is the Host ID?

Answer:

Host ID is 82.19.54 or 01010010.00010011.00110110

Explanation: In the case of class A, last three byte of the IP address is known as Host ID.

D. What is the Network ID?

Answer:

Network ID is  14 or 01010010

Explanation: In the case of class A, first one byte of the IP address is known as Network ID.

E. What is the directed broadcast address?

Answer:

Directed broadcast address is 14.255.255.255 or 00001110.11111111.11111111.11111111

Explanation: In the case of Directed broadcast address, all the bits of host portion of IP address are ones in binary or 255 in decimal, (but network-ID remains unchanged).

N.B. Whether you face any problem then share with me in the comment section, I'll happy to help you.

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