Question

I need help with these two

1 The table below shows time, temperature, and temperature change data collected using Pivot Lab#8 (Specific Heat of Water Experiments). The heat supplied, Q, is to be calculated from Q = Pt (where P is the power of the light bulb which is 25 watts and t is the time). For example, when t = 200 s, Q = 25 watts x 200 s = 5000 Joules. Plot Temp. Change (vertical axis) versus Heat Supplied (horizontal axis) and find the slope (use MS Excel). Then calculate the specific heat, c, from c = slopex mass. The mass of the water is 1231g (as the scale reads). What is the specific heat of water, c, according to the data? 1. Use this table and graph to collect and analyze data. Follow the instructions below. Temperature Temp. Change Heat Supplied Degree C Celsius Degree Joule, 22.1 0 2 200 22.7 0.6 3 400 23.4 1.3 600 242 2.1 800 25 2.9 1000 25.7 3.6 Time S 4 5 6 O c=4.18 J/g °C OC -5.34 J/g °C C = 6.44 J/g °C OC - 8.12 J/g °C O c=4.98 J/g °C

Answer 1

DATE: 0 Batch No... Temp change in le N 410 4 3.0 2.0 B O 10 B SUDO 10000 15000 20000 2 SDÓD Hent supplied in

2.9-10 Slope of the graph, ma AB BC - = 0.0001461 20000 - 7000 13000 = 1.231 kg. 141 0.0001461 x1.231 Mass of water, m=1231 Specific heat, ca Slope x mass = 5340 J/kg.°c * C=5.345/91°C = 5.345/9. °C A. This is correct as some light energy can escape the beaker, B. This is correct as beaker is not insulated and some energy can escape (. This is correct as the power rating may not be acaurale D. This is correct as the beaker itself abscob some of the heat .. the correct option is: * All of the above .