Question

वे/, Solue h= o2 uen yo Prom o to xvalues Kuta mathod Range 7

Answer 1

afy h2o.2, Yo=0.8 for o=0 4. Given that dia daty h=0.2, you de esta fim, ay gud 02x2!.. Runge-Kutta method of ath order ü . yenth) = y(x) of % [ F +262 +2F3+ FA). . fioch frig) F2 = chf (meh, yeah) F 2 h. flnek, ye Faz/) Pa a h. forth, gefs)

WWWWW Now, here x20 and 2 20.8, then and flam) = vary then ha h. flary) = 0.2x Vort 0.8 20.1789 fra h. . (x+2, 7+). 70.2 +10.1, 0.889) 2012 X Vint8:889 20:1896 1.f3'chi f(444, yen) -0.2 * HO.1,0.895) 202 10.1) 0.895 3 0.1903 the chitath, 2023) 202xf(0.2, 0.990) 0.2020 z [F1+2 F2 + 2 F3 + F4] +0. 20301 y(2) +/ ) = 0.8 0.1789 + 2x 0.1896 + 2 x 0.1903 20. 84 0.42575 ? 1.226 Now, 34= 0.2 and 1 = 1226 and again ħ z ch. Hany) = 0-2 * $(0:2, 1.226) 20.2 von 1.256 = 0.225 6 ~ 6. + 4 +, ). B. 46.2 , .332 20.2 x 16.39%87.3385 = 0.2390 f32 h. vareh, gta a h. of (0.3, 1.3455) 20.2396 Frana hafa faz nf (24th, gefs) a hf (0-4, J. 4656) = 0.2695.

.42 0712486) = 7, (a) + [44272+253 +84] ya 764) - 1.226 +46 (0.2254212290 +2%•2396 7.2695] 2 1.468 Again, q. = 24 and 2 1468 Similar way if you procede a you will ke get ho aus y when the & vatice will re 1 then it will be fop. That no he will re=1 as h20.2.