A 0.49 cm high object is placed 8.8 cm in front of a diverging lens whose...
A 0.49 cm high object is placed 8.5 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image?
A 0.44 cm high object is placed 8.4 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image?
A 4.0 cm tall object is placed 12.0 cm in front of a diverging lens. When the image of the object is measured it is found to measure 1.3 cm in height. What is the focal length of the lens? Draw a ray diagram with the object, image and focal points labeled.
An object 10 cm tall is placed 50 cm in front of a diverging lens with a focal length of 10 cm. a. find the image location b. what is the magnifications? c. what is the height of the image?
Course Contents.. » Set 8 (due Thurs 3/ 29 at 11:59PM) Height of Image Tin A 0.54 cm high object is placed 8.6 cm in front of a diverging lens whose foca?length is 7.5 cm what s the height of the image? Incorrect. Tries 2/20 Previous Tries Post Discussion
An object of height 2.8 cm is placed 27 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length.Part (a) Find the location of the final image, in centimeters beyond the converging lens. Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
Use the thin lens equation to solve problems 14 –18. 14. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 15. An object is 10 cm high and is placed 16 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 16. An object is...
An object is placed 14.0 cm in front of a lens of focal length 5.08 cm. Another lens of focal length 4.48 cm is placed 1.83 cm past the first lens. Where is the final image (how far past the lens with focal length 4.48 cm)? 2.59 cm You are correct. Your receipt no. is 158-1618 Priwinuti Tiit Is it real or virtual? Incorrect The image is virtual Correct: The image is real You are correct. Your receipt no. is...
2) A diverging lens is placed 20. cm away from an object, 80. cm from the diverging lens is a converging lens whose focal length is 25 cm. 35. cm from the converging lens is a screen showing an image of the object. a) What is the focal length of the diverging lens? f = 25. cm o *20. cm → 80. cm + 35 cm → b) What type of image is it? Circle one Real or Virtual c)...
An object is 27 cm in front of a diverging lens that has a focal length of -20 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.6?