A 0.44 cm high object is placed 8.4 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image?
A 0.44 cm high object is placed 8.4 cm in front of a diverging lens whose...
A 0.49 cm high object is placed 8.5 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image?
A 0.49 cm high object is placed 8.8 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image? 405cm Subet Arowe Incorrect. Tries 6/20 Previous Tries Post Discussion Send Feedback
A 4.0 cm tall object is placed 12.0 cm in front of a diverging lens. When the image of the object is measured it is found to measure 1.3 cm in height. What is the focal length of the lens? Draw a ray diagram with the object, image and focal points labeled.
An object 10 cm tall is placed 50 cm in front of a diverging lens with a focal length of 10 cm. a. find the image location b. what is the magnifications? c. what is the height of the image?
An object of height 2.8 cm is placed 27 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length.Part (a) Find the location of the final image, in centimeters beyond the converging lens. Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
2) A diverging lens is placed 20. cm away from an object, 80. cm from the diverging lens is a converging lens whose focal length is 25 cm. 35. cm from the converging lens is a screen showing an image of the object. a) What is the focal length of the diverging lens? f = 25. cm o *20. cm → 80. cm + 35 cm → b) What type of image is it? Circle one Real or Virtual c)...
Where is the image if an object is placed 16 cm in front of a diverging lens, whose focal point is 3 cm away from the lens?
An object is placed in front of a diverging lens with focal length of −70 cm. Find the location of the image and the characteristics of the image (real or virtual, enlarged or reduced, and upright or inverted) for each object distance. Also draw the ray diagram for each object distance. a) 100 cm b) 40 cm
A 5-cm-tall object is 7.5 cm in front of a diverging lens that has a 10 cm focal length. Use ray tracing to find the position and height of the image. To do this accurately, use a ruler and paper with a grid. Determine the image distance and image height by making measurements on your diagram.