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At what horizontal velocity would a satellite have to be launched from the top of Mt....

At what horizontal velocity would a satellite have to be launched from the top of Mt. Everest to be placed in a circular orbit around the Earth?

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Answer #1

To solve this problem, first of all we will assume that the difference in gravity at the top of everest is the same as at sea level.

Again we will also assume that there is no wind resistance at that altitude (this isn't a reasonable assumption).

Now, use the equation:
a = v^2/r
=> a = g = 9.81 m/s^2
Again, r = radius at the top of Mt. Everest = 6,380,000 meters

solve for v
v = sqrt (a * r)
=> v = sqrt [(9.81 m/s^2)*(6,380,000 m)]
=> v = 7,910 m/s

Therefore, the requisite horizontal velocity of the satellite = 7,910 m/s.

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