Question

Q1. (20 points) Write an application that displays a table of the binary, octal and hexadecimal equivalents of the decimal numbers in the range 1 through 256. Make sure to write logic to ascertain these equivalents of the decimal numbers, not use some library methods. If you aren’t familiar with these number systems, refer the Number systems document provided to you. Include the screenshot of the sample run.

With the java language. Preferably by passing an array to the binary, hex, and octal functions.

Answer 1

/*********************************NumberConversion.java*************************/

public class NumberConversion {

   public static void main(String[] args) {

       System.out.println("In Binary:");

//You can change array according to you
       binary(new int[] { 12, 34, 55, 66, 256 });// calling binary method
       System.out.println("In Octal: ");
       octal(new int[] { 12, 34, 55, 66, 256 }); // calling octal method
       System.out.println("In Hexadecimal: ");
       hex((new int[] { 12, 34, 55, 66, 256 })); // calling hex method
   }

   /*
   * binary method to convert decimal values to binary
   */
   public static void binary(int[] nums) {

       for (int i = 0; i < nums.length; i++) {
           String s = "";

           int n = nums[i];
           while (nums[i] > 0) {
               s = nums[i] % 2 + s;
               nums[i] = nums[i] / 2;
           }

           System.out.println(n + " --------->" + s);
       }
   }

   /*
   * octal method for convert decimal to octal
   */
   public static void octal(int[] decimals) {

       char octalchars[] = { '0', '1', '2', '3', '4', '5', '6', '7' };
       for (int i = 0; i < decimals.length; i++) {
           int rem;
           String octal = "";
           int n = decimals[i];
           while (decimals[i] > 0) {
               rem = decimals[i] % 8;
               octal = octalchars[rem] + octal;
               decimals[i] = decimals[i] / 8;
           }
           System.out.println(n + "----------->" + octal);
       }

   }

   /*
   * hex method for converting decimal values to hexadecimal values
   */
   public static void hex(int[] nums) {

       char hex[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };
       for (int i = 0; i < nums.length; i++) {
           // to storing remainder
           int rem;
           // to storing result
           String hexS = "";
           int n = nums[i];
           while (nums[i] > 0) {
               rem = nums[i] % 16;
               hexS = hex[rem] + hexS;
               nums[i] = nums[i] / 16;
           }

           System.out.println(n + "----------->" + hexS);
       }
   }
}

/*******************************output*************************/

In Binary:
12 --------->1100
34 --------->100010
55 --------->110111
66 --------->1000010
256 --------->100000000
In Octal:
12----------->14
34----------->42
55----------->67
66----------->102
256----------->400
In Hexadecimal:
12----------->C
34----------->22
55----------->37
66----------->42
256----------->100

Console x <terminated> NumberConversion [Java Applicat In Binary: 12 ->1100 34 ->100010 55 >110111 66 ->1000010 256 >100000000 In Octal: 12- ->14 34- ->42 55- >67 66- >102 256-- ->400 In Hexadecimal: 12- -->C 34- >22 55- >37 66- >42 256- ->100

Please let me know if you have any doubt or modify the answer, Thanks