Question

1. The interaction between two molecules is as shown in the graph. When the molecules are separated by 2.0A, they are momentarnily at rest n Pairwise Potential a) What is the maximum kinetic energy of the molecules? [Al b) 1.5 x 10 energy? J of energy is removed from the system. What is the resulting Eus and what is the minimum kinetic

Answer 1

From the graph when the molecule are separated by 2 A^0, then P.E P.E = -1 times 10^- 20 J & K.E = 0[from Question] because E = P.E + K.E E = -1 times 10^- 10 + 0 E = -1 times 10^- 20 J Now the maximum kinetic Energy will be, when P.E is minimum E = (P.E)_min + (K.E)_max - 1 times 10^- 20 J = -4 times 10^- 20 + (K.E)_max (K.E)_max = 3 times 10^- 20 J (b) when 1.5 times 10^- 21 J is removed then E_total = -1 times 10^- 20 - 1.5 times 10^- 21 E_total = -1.15 times 10^- 20 J And minimum K.E will be zero because K.E can�t be negative