Question

Consider the following code segment: int main() cons int SIZE -20; int values [SIZE] - f0, 23, 34, -7, 110, 42,-350, 424, 25, 99, 10, 05, 50, -5, 1, 200, -350, 437, 25, 147}; // your code goes here Write a complete program to display the values from each of the following four steps All displays must be done in main. Use separate functions for each step below, passing the array to each function. 1.1) Provide the sum of the numbers in this array - function must return an int. 1.2) Provide the average of the positive numbers in this array - function must return a double. 1.3)Provide the lowest number in the array -function must return an int. 1.4) Provide the highest number in the array - function must return an int.

Answer 1

#include <stdio.h>

int sum(int n , int *arr){
    int ans = 0;
    for(int i=0;i<n;i++){
        ans = ans+arr[i];
    }
    return ans;
}

double avg(int n , int *arr){
    double ans = 0;
    for(int i=0;i<n;i++){
        ans = ans+arr[i];
    }
    return ans/n;
}

int minimum(int n , int *arr){
    int ans = arr[0];
    for(int i=1;i<n;i++){
        if(arr[i]<ans){
            ans = arr[i];
        }
    }
    return ans;
}

int maximum(int n , int *arr){
    int ans = arr[0];
    for(int i=1;i<n;i++){
        if(arr[i]>ans){
            ans = arr[i];
        }
    }
    return ans;
}

int main(){
    const int SIZE = 20;
    int values[SIZE] = {0,23,34,-7,110,42,-350,424,25,99,10,05,50,-5,1,200,-350,437,25,147};
    printf("Sum = %d\n",sum(SIZE,values));
    printf("Avg = %lf\n",avg(SIZE,values));
    printf("min = %d\n",minimum(SIZE,values));
    printf("max = %d\n",maximum(SIZE,values));
    printf("");
}

OUTPUT :

"D:\Coding CODE BLOCKSISampleCpp\bin\DebuglSampleCpp.exe Sum 920 Avg 46.000000 min-350 max437 Process returned e (exe) execution ti Press any key to continue. me : 0.547 s