Solution:
The following null and alternative hypotheses need to be tested:
Ho: μ1 = μ2 = μ3
Ha: Not all means are equal
The above hypotheses will be tested using an F-ratio for a One-Way ANOVA
Using excel,
First enter data in excel,
Data -------> Data analysis-------> one way anova with single factor
Input range: select all data
Alpha: 0.05
Ok
Output is:
Since it is observed that Fobt=4.461>Fcrit=3.555, it is then concluded that the null hypothesis is rejected.
Conclusion: It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that not all 3 population means are equal, at the α=0.05 significance level.
Done
We are interested in understanding the impact of ambient temperature on walker aggression. Researchers took three...
summatize the following info and break them into differeng key points. write them in yojr own words
apartus
6.1 Introduction—The design of a successful hot box appa- ratus is influenced by many factors. Before beginning the design of an apparatus meeting this standard, the designer shall review the discussion on the limitations and accuracy, Section 13, discussions of the energy flows in a hot box, Annex A2, the metering box wall loss flow, Annex A3, and flanking loss, Annex...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated sludge operation that adversely affect effluent quality with origins in the engineering, hydraulic and microbiological components of the process. The real "heart" of the activated sludge system is the development and maintenance of a mixed microbial culture (activated sludge) that treats wastewater and which can be managed. One definition of a wastewater treatment plant operator is a "bug farmer", one who controls the aeration...