The reaction between chloride salt and concentrated sulphuric acid -
Answer :- liberates hydrogen chloride
1
Explanation :-
When chloride sallt \(\mathrm{NaCl}\) (or \(\mathrm{MgCl}_{2}\) ) reacts with conc. sulphuric acid \(\mathrm{H}_{2} \mathrm{SO}_{4}\) it gives sodium sulphate (or magnesium sulphate) and liberates hydrogen chloride gas.
\(2 \mathrm{NaCl}_{(s)}+\mathrm{Conc.H}_{2} \mathrm{SO}_{4(l)} \rightarrow \mathrm{Na}_{2} S O_{4(s)}+2 \mathrm{HCl}_{(g)} \uparrow\)
or
\(\mathrm{MgCl}_{2(s)}+\) Conc. \(\mathrm{H}_{2} \mathrm{SO}_{4(l)} \rightarrow \mathrm{MgSO}_{4(s)}+2 \mathrm{HCl}_{(g)} \uparrow\)
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