Question

September 25, 2019 Show all work, logic and equations necessary to derive the answers. Start with equation, substitution with units, sample algebra, and answer with units, cire 0.3 A batter pops a ball up in the air and the ball is caught at the same height it was hit 3.0 later. Determine (a) The maximum height the ball reaches [4] (b) The speed of the ball when it was hit. [4] to 3.0s a) Knox - - t = 20 =

Answer 1

We know that Time of ascent = Time of deseent zt t-1-5 sec For descent, where, (a) S = ut + y2962 u=0 a=g S=H t21.5 see H = 1 / 1 g +² 79.8 x 1,5 = H = 11.0am (b) V-utat manimum height, At V-0 aang u=gt = 9.8x1.5 u = 14.7 m/s

Hence the answers are,

(a) H = 11.02 m

(b) Initial velocity, u = 14.7 m/s

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