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done gravity, and (c) the normal force. (d) What is the net work the package on 9. I A tow truck pulls a car 5.00 km along a horizontal roadway using a cable having a tension of 850 N. (a) How much work does the cable do on the car if it pulls horizontally? If it pulls at 35.09 above the horizontal? (b) How much work does the cable do on the tow truck in both cases of part (a)? (c) How much work does gravity do on the car in part (a)?

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Answer #1

Work done = F.d = F d cos(theta)

(A) W = (850 N) (5000 m) cos(0)

W = 4.25 x 10^6 J  

(B) W = (850 N) (5000 m) cos35

W = 3.48 x 10^6 J

(c) W = m g d cos90

and cos90 = 0

W = 0

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