Part A N2(g)+3Br2(g)⇌2NBr3(g) K=[NBr3]2[N2][Br2]3 K=[N2][Br2]3[NBr3]2 K=[NBr3][N2][Br2] K=[NBr3]2[N2][Br2]3 Part B C(s)+O2(g)⇌CO2(g) K=[CO2][O2] K=[O2][CO2] K=[CO2][O2] K=[CO2][O2][C] When heated, carbon reacts with water to produce carbon monoxide and hydrogen. C(s)+H2O(g)+heat⇌CO(g)+H2(g) Part C What effect does each of the following changes have on the equilibrium? Drag the appropriate stresses to their respective bins. add H2O, Add heat, lower temperature, remove CO Categories: Equilibrium shifts to products, Equilibrium shifts to reactants, Equilibrium doesn't shift
5. Given the following chemical equilibria, N2(g) + O2(g) = 2 NO(g) N2(g) + 3 H2(g) = 2 NH3(g) H2(g) + 1/2 O2(g) =H2O(g) Determine the method used to calculate the equilibrium constant for the reaction below. 4 NH3(g) + 5 O2(g) = 4 NO(g) + 6 H2O(g) K
Determine the value of K for the balanced reaction, 2 NOCl(g) ↔ N2(g) + O2(g) + Cl2(g) at 291 K given the following information, 2 N2(g) + 2 O2(g) ↔ 4 NO(g); K = 5.397×10-61 NO + 1/2 Cl2(g) ↔ NOCl(g); K = 2.432×104
14.49. If the equilibrium constant K, for the reaction N2(g) + O2(g) – 2 NO(g) is 1.5 X 10%, in which direction will the reaction proceed if the partial pressures of the three gases are all 1.00 X 10-3 atm?
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) = 2NO(g) Ke = 4.3 x 10-25 2NO(g) + O2(g) + 2NO:(8) K-6.4 x 10 Determine the values of the equilibrium constants for the following equations at the same temperature: (a) 4NO(g) = N2(g) + 2NO:(g) x 10 (b) 4NO:() = 2N:(0) + 40:(8) x 10 (c) 2NO(g) + 2NO3(g) = 30:(g) + 2N:(g) x 10
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) = 2NO(g) Ke = 4.3 x 10-25 2NO(g) + O2(g) + 2NO:(8) K-6.4 x 10 Determine the values of the equilibrium constants for the following equations at the same temperature: (a) 4NO(g) = N2(g) + 2NO:(g) x 10 (b) 4NO:() = 2N:(0) + 40:(8) x 10 (c) 2NO(g) + 2NO3(g) = 30:(g) + 2N:(g) x 10
Given the following reactions, (1) 1/2 N2(g) + 1/2 O2(g) ⇌ NO(g) Kc = 4.8×10^−10 (2) 2 NO(g) + O2(g) ⇌ 2 NO2(g) Kc = 9.1× 10^4 calculate Kc for the reaction below. (3) 2 NO2(g) ⇌ N2(g) + 2 O2(g) Kc = ???
Leilibrium 11. IfKc = 7.5 x 10-9 at 1000 K for the reaction: N2(g) + O2(g) (a) What is Kp at 1000 K for the reaction? 22 NO(g) (b) What is Kc for the reaction 12 N2(g) + 1/2O2(8) NO(g)
N2(g) + O2(g) equilibrium reaction arrow 2 NO(g); Kc = 5.6 ✕ 10−4 at 2098 K (a) What is the value of Kc for the reaction 2 NO(g) equilibrium reaction arrow N2(g) + O2(g) at the same temperature? (b) What is the value of Kc for the reaction 1/2 N2(g) + 1/2 O2(g) equilibrium reaction arrow NO(g) at the same temperature? (c) Does the equilibrium in (a) favor the reactant or the products? reactant products (d) Does the equilibrium in...
Determine the value of K for the balanced reaction, 2 NOCl(g) ↔ N2(g) + O2(g) + Cl2(g) at 279 K 2 N2(g) + 2 O2(g) ↔ 4 NO(g); K = 6.503×10-62 NO + 1/2 Cl2(g) ↔ NOCl(g); K = 4.122×104