If C1=4.3 ?F, C2=5.1 ?F, C3=3.7 ?F and C4=6.5 ?F, what is the equivalent capacitance of this capacitor network?
C2 & C3 are in parallel so their equivalent capacitance = 5.1 + 3.7 = 8.8 F
These are in series with C1 and C4 so the circuit's equivalent (total) capacitance = Ceq
1/Ceq = 1/4.3 + 1/8.8 + 1/6.5 = 0.500040657
solving this, we get
Ceq = 1.999837 = 2 F (approx)
so, the equivalent capacitance of this capacitor network is 2 F
If C1=4.3 ?F, C2=5.1 ?F, C3=3.7 ?F and C4=6.5 ?F, what is the equivalent capacitance of...
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