Homework Answers
(1) Since pKa1 (6.351) < pH (8.70) < pKa2 (10.329)
=> predominant species at pH 8.70 is
HCO3-
(2) pH = pKa2 + log([CO32-]/[HCO3-])
9.90 = 10.329 + log([CO32-]/[HCO3-])
log([CO32-]/[HCO3-]) = -0.429
[CO32-]/[HCO3-] = 10^(-0.429) = 0.372
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