Question

Question 2: Answer all parts Consider the task involving two pneumatic cylinders A and B, as shown in Figure Q2, that have to be actuated in sequences by means of solenoid activated control valves Each cylinders position is interrogated by means of two magnetic reed switches. X002 X003 X004 X005 Start CYLINDERA CYLINDER B Stop Y000 Y001 Y002 Y003 Start switch [X000] Stop switch X001 Solenoi Cylinder A X002] Cylinder A+ [X003] Solenoid (B-) Y003] Cylinder B X004] Cylinder B+ [X005] Solenoid (A+)TY000] Solenoid (B+) [Y002] *Start switch is nomaly open & spring retumed ** Stop switch is nomally closed & spring returned- when depressed sequence should stop immediately Figure Q2 For each sequence below i. Implement a ladder logic PLC program ii. Indicate any internal locations you may use IExplain the solution Sequence 1: A to the right, B to the right, B to the left, A to the left Sequence to run continuously (15 marks) uence 2: A to the right, B to the right, 10 second delay, A to the left, B to the left (i.e. A+, B+, A-, B-) Sequence to repeat 5 times only (15 marks)

Answer 1

Py C) fic う Sequence 1 Solution Here X000 is a start switch. Once the start switch is ON i.e. 1', output Y000 is ON i.e. the solenoid At is done. Once Y000 is ON, X003 becomes '1', and output Y002 is ON i.e. the solenoid B+ is done. Similarly X005 becomes 1', and output Y003 is ON i.e. the solenoid B. is done. Then X004 becomes 11, and output Y001 įs ON ǐ.e. the solenoid A-ls done. Once the outpt YO01 İn '1, then its send to first rail and the process continues. Sequence 2 Solution: Here X000 is a start switch and the counter C5 is used. Once the start switch is ON i.e. '1',the counter starts to count, the cu bit becomes '1' then output Y000 is ON i.e. the solenoid A+ is done. Once Y000 is ON, X003 becomes '1', and output Y002 is ON i.e. the solenoid B+ is done. Then x005 is glven to a timer, as X005 is 1' timer starts, it counts till 10 sec as the preset value is 10. After 10 sec the done bit i-e. DN bit becomes '1', and output YOOI İS ON i.e. the solenoid A. is done. Then X002 becomes '1', and output Y003 is ON i.e. the solenoid A- is done. Once the outpt YO03 in 1' then its send to first rail and the process continues till the counter counts 5, as the preset value is 5