Question

ASSEMBLY LANGUAGE

The matrix (two-dimensional array) with ROWS and COLS dimensions of integer values is given. Perform various matrix processing activities according to the algorithms below. Store the results into the output vector (one-dimensional array) with appropriate size.

For Grade 7) Count the number of odd values (n mod 2 <> 0) for each row.

For Grade 9) Calculate the sum of positive values for each column.

To obtain inputs and return the results, define appropriate type C/C++ functions. Please use the following template as a base for solution:

#include "stdafx.h"

#include <cstdio>

#include <cassert>

// For each grade level variant implement own function, e.g.:

void solution_for_grade_X(const int * arr, size_t arr_rows, size_t arr_cols, int * result)

{

    __asm

    {

        // Your Inline Assembler instructions for grade X level go here

        // :::

    }

}

const int ROWS = 2;

const int COLS = 3;

int main()

{

    // Change the array definitions to be appropriate for your assignments:

    int data1[ROWS][COLS] = { { 0, -1, 2 }, { 3, 4, -5 } };

    int result1[ROWS]; // Note: for some assignments the result size will depend on the COLS!

    // Change the parameters according to your assignment function, e.g.:

    solution_for_grade_X((const int *)data1, ROWS, COLS, result1);

    // Print the result one-dimensional array to the console:

    for (size_t i = 0; i < ROWS; i++)

        printf("%d ", res1[i]);

    // :::

    return 0;

}

Answer 1

#include <iostream>
#include <cstdio>
#include <cassert>
using namespace std;

// For Grade 7) Count the number of odd values (n mod 2 <> 0) for each row

void solution_for_grade_7(const int * arr, size_t arr_rows, size_t arr_cols, int * result)

{
     for(int i = 0 ; i < arr_rows ; i ++){

         int numOdVals = 0;

         for(int j = 0; j < arr_cols ; j++){
             if( ((*arr)%2) != 0){
                 numOdVals++;

             }
             arr++;

         }
         (*result) = numOdVals;
         result++;
     }

}
//For Grade 9) Calculate the sum of positive values for each column.
void solution_for_grade_9(const int * arr, size_t arr_rows, size_t arr_cols, int * result)

{
    for(int i = 0 ; i < arr_rows ; i ++){

        int numOdVals = 0;

        for(int j = 0; j < arr_cols ; j++){
            if(*arr > 0){
                *(result+j) = *(result+j) + *arr;
            }

            arr++;
        }

    }

}
//Number of rows
const int ROWS = 2;
//Rows of columns
const int COLS = 3;

int main(int argc, char *argv[])
{
    // Change the array definitions to be appropriate for your assignments:

        int data1[ROWS][COLS] = { { 0, -1, 2 }, { 3, 4, -5 } };

        int result1[ROWS]; // Note: for some assignments the result size will depend on the COLS!

        // Change the parameters according to your assignment function, e.g.:

        solution_for_grade_7((const int *)data1, ROWS, COLS, result1);

        // Print the result one-dimensional array to the console:

        for (size_t i = 0; i < ROWS; i++)

            printf("%d ", result1[i]);

        // /For Grade 9) Calculate the sum of positive values for each column.

         int result2[COLS] = {0};
         solution_for_grade_9((const int *)data1, ROWS, COLS, result2);

         // Print the result one-dimensional array to the console:

         for (size_t i = 0; i < COLS; i++)

             printf("%d ", result2[i]);

        return 0;
}