22.5 Question 14 (4 points) A 5-kg block is sliding across a level floor at 15...

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Answer 1

Answer #1

Frictional force acting on the body against the movement.

Given velues are

Initial velocity,u =15m/sec

Final velocity,v = 0m/sec ( stops sliding)

Acceleration due to gravity,g =10

Mass of the body ,m = 5 kg

Coefficient of kinetic friction,mk =.4

Frictional force,f = mk*m*g

f= .4*5*10=20N

ma= 20 N

Deceleration,a= 20/m

a= 4 m/s2

v = u + a* t

0 = 15- 4*t (negative sign represent force is against the movement)

t = 3.75 seconds

Hence,3.75 seconds take to slide before stopping.

Answer 2

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