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Nameindulia Los Drosophila Genetics Predictions-L113 (20 pts.) Part I. Meiosis and Punnett Squares Remember, whenever you use

(sex chromosomes) Background on Halloween + full moon-dependent recessive traits: (Note: vocabulary words are highlighted bel

b. (0.25pt) What is the genotype of this gamete drawn above? 2. A wildtype male would not demonstrate these traits, and thus

C. (3pts) What phenotypes will be produced among the offspring of this cross? And what will be the expected ratio of these ph

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Answer #1

ANSWER 1.A :-

  1. First of all, the characters of fire breathing and laser projection are encoded by the autosome or the non-sex chromosomes. The germ cells are the ones which undergo the process of meiosis in order to produce the gametes and in this case the egg cells.
  2. So, the autosomal characters won't be segregated as a part of meiotic division but is restricted to mitotic division.
  3. So, the entire individual is able to produce all the cells which may be able to display the desired traits encoded by the autosomal genes. The eggs that will be produced will be having all X-chromosomes although there will be production of polar bodies thereby restricting the chromosome to only a single egg cell as the polar bodies are reutilized by the organism. Still, the representation of segregation of chromosome into gametes is as follow :-

ANSWER 1.B :-

The genotype of this gamete will be (3 + X) in which three represents the number of autosome and X indicates the sex chromosome. (b/d) should be the correct representation for the autosomes.

ANSWER 2.A :-

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  1. Taking into consideration, the male drosophila will get segregated forming 4 sperm cells and will show presence of either X-chromosome or Y-chromosome along with the dominant form of the alleles according to the condition mentioned in the question.

ANSWER 2.B :-

The genotype of the male drosophila should be (3 + X/Y) in which three represents the number of autosomes and X/Y indicates the sex chromosomes. (D/B) should be the genotype for the autosomes in consideration.

ANSWER 3.A :-

The autosomal genotype which is considered here should be (Dd/Bb) which indicates that the combination will be heterozygous. This will be the condition for both the males and the females.

ANSWER 3.B :-

The offsprings would not be having the mutated form of the genes in homozygous recessive condition and hence the normal wild-type phenotype will be seen.

ANSWER 3.C :-

If the offsprings are self-crossed, a Mendelian ratio of 9:3:3:1 for the autosomal genes will be obtained. There will be 9 wild type individuals, 3 will show mutated gene for fire breathing and wild type/unmutated laser shooting gene, 3 will be show wild type/unmutated fire breathing gene and mutated laser shooting gene and 1 will show both the mutated forms.

​​​​​​​Note :- Respected Sir/Madam, for any doubts, please prefer communicating through the comment section and please provide an upvote if the answer seems satisfactory.

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