ANSWER 1.A :-
ANSWER 1.B :-
The genotype of this gamete will be (3 + X) in which three represents the number of autosome and X indicates the sex chromosome. (b/d) should be the correct representation for the autosomes.
ANSWER 2.A :-
ANSWER 2.B :-
The genotype of the male drosophila should be (3 + X/Y) in which three represents the number of autosomes and X/Y indicates the sex chromosomes. (D/B) should be the genotype for the autosomes in consideration.
ANSWER 3.A :-
The autosomal genotype which is considered here should be (Dd/Bb) which indicates that the combination will be heterozygous. This will be the condition for both the males and the females.
ANSWER 3.B :-
The offsprings would not be having the mutated form of the genes in homozygous recessive condition and hence the normal wild-type phenotype will be seen.
ANSWER 3.C :-
If the offsprings are self-crossed, a Mendelian ratio of 9:3:3:1 for the autosomal genes will be obtained. There will be 9 wild type individuals, 3 will show mutated gene for fire breathing and wild type/unmutated laser shooting gene, 3 will be show wild type/unmutated fire breathing gene and mutated laser shooting gene and 1 will show both the mutated forms.
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Nameindulia Los Drosophila Genetics Predictions-L113 (20 pts.) Part I. Meiosis and Punnett Squares Remember, whenever you...
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