Solution :
Given that,
mean = =58,000 miles
standard deviation = =1,800 miles
A ) P ( x > 55,060 )
= 1 - P (x < 55,060 )
= 1 - P ( x - /
) < ( 55,060 - 58,000 / 1,800
)
= 1 - P ( z < - 2940 / 1,800 )
= 1 - P ( z < - 1.63)
Using z table
= 1 - 0.0516
= 0.9484
Probability = 94.84%
B ) P( x < 59,280)
P ( x - /
) < ( 59,280 - 58,000 / 1,800
)
P ( z < - 5 / 1,800 )
P ( z < 0.71 )
Using z table
0.7611
Probability = 76.11%
Fast Service Truck Lines uses the Ford Super Duty F-750 exclusively. Management made a study of...
5.00 points Fast Service Truck Lines uses the Ford Super Duty F-750 exclusively. Management made a study of the maintenance costs and determined the number of miles traveled during the year followed the normal distribution. The mean of the distribution was 60,000 miles and the standard deviation 2,000 miles. (Round z- score computation to 2 decimal places and your final answer to 2 decimal places.) eWhat percent of the Ford Super Duty F-750s logged 65,200 miles or more? Percent What...
5. value 10.00 points Fast Service Truck Lines uses the Ford Super Duty F-750 exclusively. Management made a study of the maintenance costs and determined the number of miles traveled during the year followed the normal distribution. The mean of the distribution was 60,000 miles and the standard deviation 2,000 miles. (Round z-score computation to 2 decimal places and your fihal answer to 2 decimal places.) (a) What percent of the Ford Super Duty F-750s logged 65,200 miles or more?...