Question

can someone explain how to solve for kp assuming this datat F() 295 301 305 311...

can someone explain how to solve for kp assuming this datat

\lambda F(\lambda) \sigma(\lambda ) \phi(\lambda )
295
301
305
311
315
319
332.5
337.5
342.5
347.5
352.5
357.5
362.5
372.5
377.5
382.5
387.5
392.5
397.5
402.5
407.5
412.5
0
0.01
0.09
0.61
1.13
1.7
10.22
10.14
11.12
11.33
13.09
11.84
13.23
1.48
1.69
1.44
1.59
1.6
1.97
2.74
2.68
2.8
11.54
13.44
15.89
18.67
24.53
24.77
34.25
37.98
37.98
40.65
43.13
47.17
48.33
53.15
55.08
56.44
59.27
58.45
60.21
57.81
59.99
56.51
0.998
0.997
0.996
0.995
0.994
0.993
0.991
0.99
0.98
0.988
0.987
0.946
0.984
0.981
0.979
0.975
0.996
0.957
0.87
0.56
0.225
0.094

kp= \sum   \phi (\lambda )\sigma (\lambda )F(\lambda )

  \lambda

0 0
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Answer #1

Just multiply F(λ)Φ(λ)σ(λ) at each λ and add all those values,
At λ = 295 , KP = 0.998*11.54*0 = 0
At λ= 301 , KP = 0.997*13.44*0.997 = 0.133996
At λ= 305 , KP = 0.996*15.89* 0.09 = 13.346081
At λ = 311, KP = 0.995*18.67*0.61 = 11.3317565
At λ = 315, KP = 0.994*24.53*1.13 = 27.5525866
At λ = 319,  KP = 0.993*24.77*1.7 = 41.814237
At λ = 332.5 , KP = 0.991*34.25*10.22 = 346.884685
At λ = 337.5 , KP = 0.99*37.98*11.12 = 418.114224
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At λ= 412.5 , KP = 0.094*56.51*2.8 = 14.873432
Just add all these values, to get KP
KP = 4067.92366

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