Question

You are gliding over Earth's surface at a high speed, carrying your high-precision clock. At points X and Y on the ground are similar clocks, synchronized in the ground frame of reference. As you pass over clock X, it and your clock both read 0. According to you, do clocks X and Y advance slower or faster than yours? When you pass over clock Y, does it read the same time, an earlier time, or a later time than yours? Reconcile any contradictions

Answer 1

Solution

As per theory of relativity, the clock which is moving at a very high speed will experience time dilation according to relation, t=t_o/(1–(v/c)²)^½ .

In this case clocks X and Y will advance faster than my clock.

When I pass over clock Y, it shows a later time than mine as my clock slows down.