Question

culatof HILUUUUU 2 Lunel U V OL... 7) 7) Forty-seven members of a bowling league sign up for a program that claims to improve bowling scores. The participants bowl a set of five games before the program begins and a set of five games again at the end to measure their improvement The mean number of points improved (over the set of five games) was r= 10. Assume the standard deviation is o= 51 and let y be the population mean number of points improved for the set of five games. To determine whether the program is effective, a test is made of the hypotheses Ho:u=0 versus H:4> 0 at the a=0.05 level. Compute the P-value 8) A recent study of business travelers claims they spend an average of $41.00 per day on meals. As a test of this claim, a random sampling of 16 business travelers found they had spent an average of $45.00 per day with a standard deviation of $3.65. What are the critical values for a two-tailed /test of this claim with a 0.05? 9) The mean annual tuition and fees for a sample of 11 private colleges was $26,5009) with a standard deviation of $6,000. A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from $31,000. i). State the null and alternate hypotheses. ii). Compute the value of the test statistic and state the number of degrees of freedom. iii). State a conclusion regarding Ho. Use the a 0.05 level of significance.

Answer 1

Hi Dear,
I have given my 100% to solve your problem.
So, please help me out by just thumbs up.
Thank you, so much

Sol x - 10 euro 6=51 in=674 7= X-el – 10 6/in Dos Sur 2 = 1.36 42 p-value- P [2+7113443] = 0.1789 x = 0.05 in= 16 Critical totest - tobinho - to.os 15 = 2.1315 QG) (1) Ho: M = 31000 vis Hill & 31000 (1) 26500, 5=6000, n=11 t - X-ll - 26500-31000 Son - 6000/ UT t = -2-48791 (11 p-value = Plt <-2.4874] = 0.0321 Here p-value=0.0321 (2=0.05 .. we reject Ho .: The mean tutton and sees for private tution is different from $31000