Question

A planet, outside out solar system, makes one rotation about its axis in 43.9 hours. With what angular speed, in rad/s, does

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Answer #1

Solution)

Given, Time, T=43.9 hrs=158040 sec

Part a)

We know,

Angular speed, w=2pi/T

Substitute values,

w=2pi/(158040)= 3.97*10^-5 rad/sec (Ans)

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Part b)

Frequency, f= 1/T= 1/158040 s= 63275.12 nHz (Ans)

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