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*مطلوب Untitled Section A current of 10 A is flowing in a wire of resistance 5 2. The power * :dissipated in the wire is 350



In FIGURE all the batteries are ideal. Find the current through 6 2 resistor * 4.0 V 1.00 3.00 ww i = 1.64 A 2.0 8.0 V 6.02 4

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Answer #1

10 A 52 VO we know that Power dissipated in this aruit series connection) > (P = I²R] p = (10) 245 p=10ors =500W © wil 41.644

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