Question

Problem 15.48 A 90 kg student jumps off a bridge with a 12-m-long bungee cord tied to his feet. The massless bungee cord has a spring constant of 410 N/m. You can assume that the bungee cord exerts no force until it begins to stretch. Part A How far below the bridge is the student's lowest point? Express your answer with the appropriate units. ? MÅ Value O Units [1] = Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B How far below the bridge is the student's resting position after the oscillations have been fully damped? Express your answer with the appropriate units. HÅⓇ O O ? [h] = Value Units Submit Request Answer

Answer 1

riven me 90kg lengtikel = ld me k = 410 r/m | (a) At the lowest bridge point, the student i in equilliberium, o Fo= Fg koy= mg m by = mg (90)19.80) 416 sy = 2.15lm A so d = htay = 12 + 9.15) Id = 14.15 m Scanned with CamScanner

died (b) when the oscilation is of Foo Fg9 koy ning all-h') = mg h = mate s h' = 1415 m +12 n's 26.8m) Scanned with CamScanner
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