Question

answer both questions

Suppose the heights of 18-year-old men are approximately normally distributed, with mean 69 inches and standard deviation 4 inches MY NOTES | ASK YOUR TEACHER USE SALT (a) What is the probability that an 18-year-old man selected at randomis between 6 and 70 inches tail (Round your answer to four decimal places.) (b) If a random sample of twenty-five 18-year old men is selected, what is the probability that the man height is between 6 and 70 inches? (Round your answer to four decimale ) (c) Compare your answers to parts(a) and (b), is the probability in part() much higher? Why would you expect this? The probability in part(b) is much higher because the standard deviation is larger for the distribution The probability in part(b) is much higher because the standard deviation is smaller for the distribution The probability in part(b) is much higher because the mean is larger for the distribution The probability in part(b) is much higher because the mean is smaller for the distribution The probability in part(b) is much lower because the standard deviation is smaller for the distribution

Answer 1

u solution Pa) probability that an 18 y cor oldman selected at random is between 68 and 70 inches tallar mean (l)69 standasdord de walion (O): 4 p(464x270) = P( 62-69 cz c 70-69) EP (-0.25 CZK 0.25) = P(Zc0:25 - P(Zc-0125) = 0.59871 – 0.00129 -> 0119742 - Ý (S8 470) = 0. (74u. b) standard devation og B = 0.8. 1225 :p (68 <xc70) = P7680 69 <2< 70.10?) = P(-1.25.CZ 1.25) ZH25)-R - P(Z21.25) -PC2C=1125) 3 0.89435 -0.10565 F 0.7887. .. o . The probability in post b is much higher I because the standard deviation is smaller for & distribution. option bis correct. 0.% .

37 D Giren data Sample size(n) = 34 I mean (4) = 8.6 standard deviation (6) = 3. 2 ) probabiuty that for 37 gets on a given runway total teni and facceoffe time will be less than 320 mini- P(*< 320 =p (828.6486). =pl Kalp < 8.6486 - 8167 Colon 5121534 ) PC2C 0.0486) P(Z <0.0923)=P(Z2009) = 0.53586, ply <32037) = 0.5389 b) fakeoff time will be more than 2755 PLF > 275) -7P/F? 7.4324). op leveres (22Et on) a P(ZZ - 2.22) al-P(22-2:22) al - Gots 0.01321 = 0.9868. plň >7.4326) = 0-9868, c) take off time between 275 and 320 p(275.35 3320) = P(7.43245 < 816486) - pp 7.4324-816 [ 312/557 Sm 32 1.6 SP(-2,22 €750:09). 5. PC Z 50.09).-P(7's - 2122) - 0.53586 - 0.0182] = 0.5227. 387 37 37 8.6486-660