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7. How long must a simple pendulum string be to have a period of 2 seconds on mars where the acceleration due to gravity at the surface is 0.376g.

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Answer #1

here,

accelration due to gravity , g' = 0.376 g

let the length of pendulam be l

time period , T = 2 * pi * sqrt(l/g')

2 = 2 * pi * sqrt(l/( 0.376 * 9.81))

solving for l

l = 0.37 m

the length of pendulam is 0.37 m

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