4) a) Calculate the period of a simple pendulum if the length of the string is...
5. What should you do to the length of the string of a simple pendulum to double its period? 7. The acceleration of gravity gets smaller as you increase your distance from the center of the Earth. For example, if you go to a height that is one earth radius above the surface of the earth the acceleration of gravity is 2.45 m/s² (g/4.0). Is the period of a pendulum longer or shorter? 8.A pendulum makes 42 cycles in 50.0...
An expression for the period of a simple pendulum with string length ℓ derived using calculus is T = 2(pi)sqrt{ ℓ /g } . Where g is the acceleration due to gravity. Use the data in the table to decide whether or not the pendulum in the experiment can be considered a simple pendulum. Explain your decision. Suppose have the ability to vary the mass m of the bob and the length f of the string. You decide to to...
(a) What is the length of a simple pendulum that oscillates with a period of 2.6 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = LM = Enter a number. Im (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.6 s...
(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = Lм %3 m (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where...
A simple pendulum uses a steel wire as the "string." The length of this wire is 1.5 m at room temperature. If the temperature is increased by 10°C, the length of the wire increases by 0.19 mm. What is the change in the period of the pendulum?
A certain simple pendulum has a period on the earth of 2 s What is its period on the surface of Mars , where g+3.71 m/s^2
If a fixed-length simple pendulum is found to have 4 times the period on an unknown planet’s surface (compared to Earth), what is the gravity on that planet?
A simple pendulum is made by hanging a 4 kg mass from a 70 cm string suspended from the ceiling. a) What will be the period of oscillation of the mass after it is started swinging? b) If the pendulum were moved to the Moon, where g=1.6 m/s^2, what would the period of oscillation be?
n 4. It's a "Seconds Pendulum!" A seconds pendulum is a simple pendulum that crosses its equilibrium position once every (a) Find the length of this pendulum. b) Our definition for the length of a meter is the distance light travels in 1/299,792, 458 s. Given your answer to part a), why do you think we don't just use the length of a seconds pendulum as our standard for the definition of a meter instead? (c) Given that the length...
1. How much is the period of 1=1.00 m long pendulum on the Moon (g = 1.600 m/s2) 4.97 sec. 2. On a planet X pendulum of the length 0.500 m makes 50.0 oscillations in 1.00 min. Find the acceleration of gravity on the planet X. g = 13.7 m/s2. 3. Find the period of small oscillations of a meter stick suspended by its end near Earth surface (assume g=9.800 m/s2). Notice that this is not a simple pendulum but...